Crystal Reports Left outer join help

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Topic: Left outer join help

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tjbarr Newbie Joined: 01 Nov 2012 Online Status: Offline Posts: 6	Topic: Left outer join help Posted: 22 Jan 2015 at 8:38am
	everyone in the database has a field in the name table with nametype = 'a' (preferred). I want to pull those with nametype = 'nick' (nickname) and also those without a nickname. I tried this: if(isNull({name_full.nametype})) then "" else if{name_full.nametype} = 'nick' then name_full.namefirst}
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kevlray Admin Group Joined: 29 Oct 2009 Online Status: Offline Posts: 1587	Posted: 22 Jan 2015 at 12:35pm
	Just because nulls and strings can be confused, try this. if len({name_full.nametype})=0 then "" else if{name_full.nametype} = 'nick' then name_full.namefirst}
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Vimal Nair Newbie Joined: 29 Dec 2014 Location: United Arab Emirates Online Status: Offline Posts: 26	Posted: 27 Jan 2015 at 1:31am
	Check whether your query is returning data with nametype ='nick' and nametype with null values. If you want to display null, there is no need of writing a formula. Just show the column value as already null is fetched. Your question is not clear whether this formula is written for filtering the data or for display of nickname. Kindly clarify.
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