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oeterrel
Newbie
Joined: 09 Jul 2012
Online Status: Offline
Posts: 4
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Topic: Finding an element of an array in a string?
Posted: 16 Apr 2013 at 2:48am |
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Good morning,
So I am sure this has to be possible--but I do not know the correct way of coding it. I have two strings. I need to see if any elements of string A are found in string B. String A and B are both function values that return strings. They work fine.
I was trying this code:
global stringvar found;
stringvar array x:=split({@string A},",");
numbervar j:=ubound(x);
stringvar y:='';
stringvar found:='N';
for i:=1 to j
do(
y:=x;
if({@string B} like '*y*') then found:='Y'
else found:='N';
)
But the results are random. I have tested the value of y, which returns what I expect--but sometimes the statement of {@string B} like '*y*' is true when it should not be, even though I can get the values of y to return and {@string B} to return and visually see that {@string B} like '*y*' SHOULD be false..
Does a more experienced coder have any ideas?
--Olivia
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joeg1962
Newbie
Joined: 01 Mar 2013
Location: United States
Online Status: Offline
Posts: 35
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Posted: 16 Apr 2013 at 3:04am |
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Perhaps an approach like the following (which I use in a report):
if instr({DOCUMENT.SUMMARY}, 'was seen in the emergency') > 0
then 1 else 0
Which checks to see if the variable Document.Summary contains the words 'was seen in the emergency'. I would imagine you could just use your two variables. y checking for >0 is for the position that this occurs; non-zero for a valid position and 0 if not found.
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oeterrel
Newbie
Joined: 09 Jul 2012
Online Status: Offline
Posts: 4
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Posted: 16 Apr 2013 at 3:06am |
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Oh, duh--never mind :) I should say
if({@string B} like '*'+y+'*') then found:='Y' of COURSE it was random, since I was looking for parts of the string that had 'y' in them, instead of the value contained in the variable y! (I feel so silly)...
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