Crystal Reports Clamp page footer

Technical Questions

Crystal Reports Forum : Crystal Reports 9 through 2022 : Technical Questions

Topic: Clamp page footer

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krishna.R Newbie Joined: 19 Apr 2011 Online Status: Offline Posts: 7	Topic: Clamp page footer Posted: 19 Apr 2011 at 8:21am
	Hello everyone, I got a problem of writing formula for the clamp page footer. Can anyone let me know how to write a formula to clamp page footer only in page 1 but not in other pages. I tried a formula: if pagenumber=1 then true else false. But throwing an error saying "a constant expression required" for the pagenumber.
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DBlank Moderator Joined: 19 Dec 2008 Online Status: Offline Posts: 9053	Posted: 19 Apr 2011 at 8:30am
	i do not know what you mean by 'clamp'. If you are trying to conditionally suppress it on page one only just use: *pagenumber=1*
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krishna.R Newbie Joined: 19 Apr 2011 Online Status: Offline Posts: 7	Posted: 19 Apr 2011 at 10:31am
	Thanks for the reply. I used pagenumber=1 also. Still getting the same error "constant expression required"
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krishna.R Newbie Joined: 19 Apr 2011 Online Status: Offline Posts: 7	Posted: 19 Apr 2011 at 10:33am
	"Clamp Page Footer" is a check box option in the section expert for the page footer. May be its new. I 'm using CR 2008
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DBlank Moderator Joined: 19 Dec 2008 Online Status: Offline Posts: 9053	Posted: 19 Apr 2011 at 11:24am
	I think it is only for 2008
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Keikoku Senior Member Joined: 01 Dec 2010 Online Status: Offline Posts: 386	Posted: 20 Apr 2011 at 2:54am
	Yes, it appeared in 2008. Never saw it in XI. If you only have 5 records on your page, instead of having a full-size page with the footer at the very bottom (lots of white space), it would omit the whitespace and display the page footer immediately.
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krishna.R Newbie Joined: 19 Apr 2011 Online Status: Offline Posts: 7	Posted: 20 Apr 2011 at 11:03am
	Yes. Can you help me out on writing a formula for that to clamp page footer only in page 1.
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krishna.R Newbie Joined: 19 Apr 2011 Online Status: Offline Posts: 7	Posted: 20 Apr 2011 at 11:05am
	I solved my problem by approaching in different way. But still want to know how to write a formula for this.
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Keikoku Senior Member Joined: 01 Dec 2010 Online Status: Offline Posts: 386	Posted: 21 Apr 2011 at 2:48am
	Unfortunately with the restrictions on the formula it doesn't seem possible. It requires all conditions to be constant values, so you can't have stuff like pagenumber, number of records, etc.
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