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cynthiakelly
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Quote cynthiakelly Replybullet Topic: need help with date(s)
     Posted: 24 Mar 2011 at 8:22am
This is a little lengthy..please bear with me.
 
We have a date-time field that doesn't necessarily have the hour:min:sec portions populated. In those cases, I have to use the a number field that contains only HHMM info.
 
I need to use either ...
 - the date-time field in its entirety
OR
 - the date portion of the date-time field concatenated with the HHMM field
 
I've been wrestling lots of date functions to create a complete date-time field, but, so far I haven't had any luck. HELP!
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DBlank
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Quote DBlank Replybullet Posted: 24 Mar 2011 at 10:21am
1. in the datetime field with the missing times do they come in as date at midnight?
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cynthiakelly
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Quote cynthiakelly Replybullet Posted: 25 Mar 2011 at 3:12am
Yes, I think that's the default.
HH:MM:SS are zero if not specified, so 00:00:00 would be midnight, the start of the day.
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cynthiakelly
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Quote cynthiakelly Replybullet Posted: 26 Mar 2011 at 7:43pm
Pinch  I have continued to search the web for an answer. Please help ..
I haven't used VB date functions in a while; and I'm relatively new to the CrystalReports environment.
 
I need to create a complete date-time field. If necessary, I can extract the year, month, and day portions from my date-time field; and, I can extract the hour and minute portions from my HHMM field.
 
I need to know what function should be used to create a complete date-time field.  I've tried CDate, but apparently I'm not formatting everything correctly. Thanks in advance for any suggestions or advice.
 
Cynthia
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yggdrasil
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Quote yggdrasil Replybullet Posted: 28 Mar 2011 at 3:27am
Possibly longwinded, but you could just build it up from strings & substrings.
The function for Datetime is
Datetime(YYYY,MM.DD,HH,MM,SS)
 
From your time function TIME   HH := totext(left(TIME,2), 0)
 and MM := totext(right(TIME,2),0)
 
(I think, if I've understood you correctly)
 
So if in your datetime function HH and MM are 00 then substitute the above.
 
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DBlank
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Quote DBlank Replybullet Posted: 28 Mar 2011 at 3:39am
sorry was out for a bit..
try
if time(datetime_field)<>time(00,00,00) then datetime_field
else
datefield + time(tonumber(if {timefield}>=1000 then
left(totext({timefield},0,''),2) else left(totext({timefield},0,''),1)),
tonumber(right(totext({timefield},0,''),2)),
00)
 
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cynthiakelly
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Quote cynthiakelly Replybullet Posted: 01 Apr 2011 at 6:22am
Thanks, you two! 
 
I combined suggestions form both of you and got the result I needed.
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